At a gathering,
14 of the people are children. The remaining group of people is divided into men and women in the ratio of 2 : 5. Each man is given 3 candies and each woman is given 4 candies. Each accompanying child receives 5 candies. Given that only 265 candies are given away to men and children, how many more adults are there than children?
Men |
Women |
Children |
3x7 |
1x7 |
2x3 |
5x3 |
|
6 u |
15 u |
7 u |
The number of adults is repeated. Make the number of adults the same. LCM of 3 and 7 is 21.
|
Men |
Women |
Children |
Number |
6 u |
15 u |
7 u |
Value |
3 |
4 |
5 |
Total value |
18 u |
60 u |
35 u |
Number of candies given away to men and children
= 18 u + 35 u
= 53 u
1 u = 265 ÷ 53 = 5
Number of adults
= 6 u + 15 u
= 21 u
Number of more adults than children
= 21 u - 7 u
= 14 u
= 14 x 5
= 70
Answer(s): 70