At a gathering,
14 of the people are children. The remaining group of people is divided into men and women in the ratio of 3 : 5. Each man is given 2 sweets and each woman is given 3 sweets. Each accompanying child receives 5 sweets. Given that only 232 sweets are given away to men and children, how many more adults are there than children?
| Men |
Women |
Children |
| 3x8 |
1x8 |
| 3x3 |
5x3 |
|
| 9 u |
15 u |
8 u |
The number of adults is repeated. Make the number of adults the same. LCM of 3 and 8 is 24.
| |
Men |
Women |
Children |
| Number |
9 u |
15 u |
8 u |
| Value |
2 |
3 |
5 |
| Total value |
18 u |
45 u |
40 u |
Number of sweets given away to men and children
= 18 u + 40 u
= 58 u
1 u = 232 ÷ 58 = 4
Number of adults
= 9 u + 15 u
= 24 u
Number of more adults than children
= 24 u - 8 u
= 16 u
= 16 x 4
= 64
Answer(s): 64
