At a gathering,
13 of the people are children. The remaining group of people is divided into men and women in the ratio of 3 : 5. Each man is given 2 candies and each woman is given 4 candies. Each accompanying child receives 6 candies. Given that only 528 candies are given away to women and children, how many less men are there than women?
Men |
Women |
Children |
2x4 |
1x4 |
3x1 |
5x1 |
|
3 u |
5 u |
4 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 8 is 8.
|
Men |
Women |
Children |
Number |
3 u |
5 u |
4 u |
Value |
2 |
4 |
6 |
Total value |
6 u |
20 u |
24 u |
Number of candies given away to women and children
= 20 u + 24 u
= 44 u
1 u = 528 ÷ 44 = 12
Number of less men than women
= 5 u - 3 u
= 2 u
= 2 x 12
= 24
Answer(s): 24