At a gathering,
13 of the people are children. The remaining group of people is divided into men and women in the ratio of 2 : 3. Each man is given 3 candies and each woman is given 6 candies. Each accompanying child receives 9 candies. Given that only 513 candies are given away to men and children, how many more adults are there than children?
| Men |
Women |
Children |
| 2x5 |
1x5 |
| 2x2 |
3x2 |
|
| 4 u |
6 u |
5 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 5 is 10.
| |
Men |
Women |
Children |
| Number |
4 u |
6 u |
5 u |
| Value |
3 |
6 |
9 |
| Total value |
12 u |
36 u |
45 u |
Number of candies given away to men and children
= 12 u + 45 u
= 57 u
1 u = 513 ÷ 57 = 9
Number of adults
= 4 u + 6 u
= 10 u
Number of more adults than children
= 10 u - 5 u
= 5 u
= 5 x 9
= 45
Answer(s): 45
