At a gathering,
25 of the people are children. The remaining group of people is divided into men and women in the ratio of 2 : 3. Each man is given 3 candies and each woman is given 5 candies. Each accompanying child receives 8 candies. Given that only 588 candies are given away to men and children, how many more adults are there than children?
Men |
Women |
Children |
3x5 |
2x5 |
2x3 |
3x3 |
|
6 u |
9 u |
10 u |
The number of adults is repeated. Make the number of adults the same. LCM of 3 and 5 is 15.
|
Men |
Women |
Children |
Number |
6 u |
9 u |
10 u |
Value |
3 |
5 |
8 |
Total value |
18 u |
45 u |
80 u |
Number of candies given away to men and children
= 18 u + 80 u
= 98 u
1 u = 588 ÷ 98 = 6
Number of adults
= 6 u + 9 u
= 15 u
Number of more adults than children
= 15 u - 10 u
= 5 u
= 5 x 6
= 30
Answer(s): 30