Lynn had some fruits at her stall.
13 of them were dates,
15 of the remainder were dragon fruits and the rest were tomatoes. The amounts earned for each date, each dragon fruit and each tomato sold are $1.50, $1.30 and $1.70 respectively. The number of dates sold to the number of dragon fruits sold to the number of tomatoes sold was 1 : 5 : 4. In total, she sold
13 of the fruits and earned $88.80. How many tomatoes did she have at first?
Dates |
Dragon Fruits |
Tomatoes |
Total |
1x5 |
2x5 |
3x5 |
|
1x2 |
4x2 |
|
5 p |
2 p |
8 p |
15 p |
The total number of dragon fruits and tomatoes is repeated. Make the total number of dragon fruits and tomatoes the same. LCM of 2 and 5 is 10.
|
Dates |
Dragon Fruits |
Tomatoes |
Number |
1 u |
5 u |
4 u |
Value |
$1.50 |
$1.30 |
$1.70 |
Total value |
1.5 u |
6.5 u |
6.8 u |
Total amount that Lynn earned
= 1.5 u + 6.5 u + 6.8 u
= 14.8 u
14.8 u = 88.80
1 u = 88.80 ÷ 14.8 = 6
Total number of fruits sold
= 1 u + 5 u + 4 u
= 10 u
= 10 x 6
= 60
Total number of fruits at first
= 60 ÷
13= 60 x 3
= 180
Total number of fruits at first
= 5 p + 2 p + 8 p
= 15 p
15 p = 180
1 p = 180 ÷ 15 = 12
Number of tomatoes that Lynn had at first
= 8 p
= 8 x 12
= 96
Answer(s): 96