Tammy had some fruits at her stall.
13 of them were mandarin oranges,
14 of the remainder were pomegranates and the rest were tomatoes. The amounts earned for each mandarin orange, each pomegranate and each tomato sold are $1.30, $1.80 and $1.60 respectively. The number of mandarin oranges sold to the number of pomegranates sold to the number of tomatoes sold was 2 : 3 : 4. In total, she sold
12 of the fruits and earned $259.20. How many mandarin oranges did she have at first?
Mandarin Oranges |
Pomegranates |
Tomatoes |
Total |
1x2 |
2x2 |
3x2 |
|
1x1 |
3x1 |
|
2 p |
1 p |
3 p |
6 p |
The total number of pomegranates and tomatoes is repeated. Make the total number of pomegranates and tomatoes the same. LCM of 2 and 4 is 4.
|
Mandarin Oranges |
Pomegranates |
Tomatoes |
Number |
2 u |
3 u |
4 u |
Value |
$1.30 |
$1.80 |
$1.60 |
Total value |
2.6 u |
5.4 u |
6.4 u |
Total amount that Tammy earned
= 2.6 u + 5.4 u + 6.4 u
= 14.4 u
14.4 u = 259.20
1 u = 259.20 ÷ 14.4 = 18
Total number of fruits sold
= 2 u + 3 u + 4 u
= 9 u
= 9 x 18
= 162
Total number of fruits at first
= 162 ÷
12= 162 x 2
= 324
Total number of fruits at first
= 2 p + 1 p + 3 p
= 6 p
6 p = 324
1 p = 324 ÷ 6 = 54
Number of mandarin oranges that Tammy had at first
= 2 p
= 2 x 54
= 108
Answer(s): 108