Mary had some fruits at her stall.
38 of them were avocados,
23 of the remainder were oranges and the rest were mandarin oranges. The amounts earned for each avocado, each orange and each mandarin orange sold are $1.50, $1.10 and $1.70 respectively. The number of avocados sold to the number of oranges sold to the number of mandarin oranges sold was 5 : 3 : 4. In total, she sold
16 of the fruits and earned $70.40. How many mandarin oranges did she have at first?
Avocados |
Oranges |
Mandarin Oranges |
Total |
3x3 |
5x3 |
8x3 |
|
2x5 |
1x5 |
|
9 p |
10 p |
5 p |
24 p |
The total number of oranges and mandarin oranges is repeated. Make the total number of oranges and mandarin oranges the same. LCM of 5 and 3 is 15.
|
Avocados |
Oranges |
Mandarin Oranges |
Number |
5 u |
3 u |
4 u |
Value |
$1.50 |
$1.10 |
$1.70 |
Total value |
7.5 u |
3.3 u |
6.8 u |
Total amount that Mary earned
= 7.5 u + 3.3 u + 6.8 u
= 17.6 u
17.6 u = 70.40
1 u = 70.40 ÷ 17.6 = 4
Total number of fruits sold
= 5 u + 3 u + 4 u
= 12 u
= 12 x 4
= 48
Total number of fruits at first
= 48 ÷
16= 48 x 6
= 288
Total number of fruits at first
= 9 p + 10 p + 5 p
= 24 p
24 p = 288
1 p = 288 ÷ 24 = 12
Number of mandarin oranges that Mary had at first
= 5 p
= 5 x 12
= 60
Answer(s): 60