Julie had some fruits at her stall.
38 of them were kiwis,
23 of the remainder were oranges and the rest were lemons. The amounts earned for each kiwi, each orange and each lemon sold are $1.60, $1.40 and $1.30 respectively. The number of kiwis sold to the number of oranges sold to the number of lemons sold was 3 : 2 : 1. In total, she sold
18 of the fruits and earned $80.10. How many kiwis did she have at first?
Kiwis |
Oranges |
Lemons |
Total |
3x3 |
5x3 |
8x3 |
|
2x5 |
1x5 |
|
9 p |
10 p |
5 p |
24 p |
The total number of oranges and lemons is repeated. Make the total number of oranges and lemons the same. LCM of 5 and 3 is 15.
|
Kiwis |
Oranges |
Lemons |
Number |
3 u |
2 u |
1 u |
Value |
$1.60 |
$1.40 |
$1.30 |
Total value |
4.8 u |
2.8 u |
1.3 u |
Total amount that Julie earned
= 4.8 u + 2.8 u + 1.3 u
= 8.9 u
8.9 u = 80.10
1 u = 80.10 ÷ 8.9 = 9
Total number of fruits sold
= 3 u + 2 u + 1 u
= 6 u
= 6 x 9
= 54
Total number of fruits at first
= 54 ÷
18= 54 x 8
= 432
Total number of fruits at first
= 9 p + 10 p + 5 p
= 24 p
24 p = 432
1 p = 432 ÷ 24 = 18
Number of kiwis that Julie had at first
= 9 p
= 9 x 18
= 162
Answer(s): 162