Linda had some fruits at her stall.
13 of them were dragon fruits,
23 of the remainder were peaches and the rest were kiwis. The amounts earned for each dragon fruit, each peach and each kiwi sold are $1.30, $1.70 and $1.90 respectively. The number of dragon fruits sold to the number of peaches sold to the number of kiwis sold was 3 : 4 : 1. In total, she sold
13 of the fruits and earned $37.80. How many kiwis did she have at first?
Dragon Fruits |
Peaches |
Kiwis |
Total |
1x3 |
2x3 |
3x3 |
|
2x2 |
1x2 |
|
3 p |
4 p |
2 p |
9 p |
The total number of peaches and kiwis is repeated. Make the total number of peaches and kiwis the same. LCM of 2 and 3 is 6.
|
Dragon Fruits |
Peaches |
Kiwis |
Number |
3 u |
4 u |
1 u |
Value |
$1.30 |
$1.70 |
$1.90 |
Total value |
3.9 u |
6.8 u |
1.9 u |
Total amount that Linda earned
= 3.9 u + 6.8 u + 1.9 u
= 12.6 u
12.6 u = 37.80
1 u = 37.80 ÷ 12.6 = 3
Total number of fruits sold
= 3 u + 4 u + 1 u
= 8 u
= 8 x 3
= 24
Total number of fruits at first
= 24 ÷
13= 24 x 3
= 72
Total number of fruits at first
= 3 p + 4 p + 2 p
= 9 p
9 p = 72
1 p = 72 ÷ 9 = 8
Number of kiwis that Linda had at first
= 2 p
= 2 x 8
= 16
Answer(s): 16