Emily had some fruits at her stall.
13 of them were pomegranates,
34 of the remainder were kiwis and the rest were grapefruits. The amounts earned for each pomegranate, each kiwi and each grapefruit sold are $1.80, $1.20 and $1.60 respectively. The number of pomegranates sold to the number of kiwis sold to the number of grapefruits sold was 1 : 3 : 4. In total, she sold
13 of the fruits and earned $153.40. How many pomegranates did she have at first?
Pomegranates |
Kiwis |
Grapefruits |
Total |
1x2 |
2x2 |
3x2 |
|
3x1 |
1x1 |
|
2 p |
3 p |
1 p |
6 p |
The total number of kiwis and grapefruits is repeated. Make the total number of kiwis and grapefruits the same. LCM of 2 and 4 is 4.
|
Pomegranates |
Kiwis |
Grapefruits |
Number |
1 u |
3 u |
4 u |
Value |
$1.80 |
$1.20 |
$1.60 |
Total value |
1.8 u |
3.6 u |
6.4 u |
Total amount that Emily earned
= 1.8 u + 3.6 u + 6.4 u
= 11.8 u
11.8 u = 153.40
1 u = 153.40 ÷ 11.8 = 13
Total number of fruits sold
= 1 u + 3 u + 4 u
= 8 u
= 8 x 13
= 104
Total number of fruits at first
= 104 ÷
13= 104 x 3
= 312
Total number of fruits at first
= 2 p + 3 p + 1 p
= 6 p
6 p = 312
1 p = 312 ÷ 6 = 52
Number of pomegranates that Emily had at first
= 2 p
= 2 x 52
= 104
Answer(s): 104