Marion had some fruits at her stall.
38 of them were guavas,
14 of the remainder were oranges and the rest were dates. The amounts earned for each guava, each orange and each date sold are $1.80, $1.60 and $1.50 respectively. The number of guavas sold to the number of oranges sold to the number of dates sold was 4 : 4 : 3. In total, she sold
116 of the fruits and earned $144.80. How many dates did she have at first?
Guavas |
Oranges |
Dates |
Total |
3x4 |
5x4 |
8x4 |
|
1x5 |
3x5 |
|
12 p |
5 p |
15 p |
32 p |
The total number of oranges and dates is repeated. Make the total number of oranges and dates the same. LCM of 5 and 4 is 20.
|
Guavas |
Oranges |
Dates |
Number |
4 u |
4 u |
3 u |
Value |
$1.80 |
$1.60 |
$1.50 |
Total value |
7.2 u |
6.4 u |
4.5 u |
Total amount that Marion earned
= 7.2 u + 6.4 u + 4.5 u
= 18.1 u
18.1 u = 144.80
1 u = 144.80 ÷ 18.1 = 8
Total number of fruits sold
= 4 u + 4 u + 3 u
= 11 u
= 11 x 8
= 88
Total number of fruits at first
= 88 ÷
116= 88 x 16
= 1408
Total number of fruits at first
= 12 p + 5 p + 15 p
= 32 p
32 p = 1408
1 p = 1408 ÷ 32 = 44
Number of dates that Marion had at first
= 15 p
= 15 x 44
= 660
Answer(s): 660