Julie had some fruits at her stall. ³₈ of them were kiwis, ²₃ of the remainder were limes and the rest were peaches. The amounts earned for each kiwi, each lime and each peach sold are $1.90, $1.70 and $1.30 respectively. The number of kiwis sold to the number of limes sold to the number of peaches sold was 1 : 2 : 3. In total, she sold ¹₁₂ of the fruits and earned $174.80. How many kiwis did she have at first?

Kiwis	Limes	Peaches	Total
3x3	5x3		8x3
	2x5	1x5
9 p	10 p	5 p	24 p

The total number of limes and peaches is repeated.  Make the total number of limes and peaches the same. LCM of 5 and 3 is 15.

	Kiwis	Limes	Peaches
Number	1 u	2 u	3 u
Value	$1.90	$1.70	$1.30
Total value	1.9 u	3.4 u	3.9 u

Total amount that Julie earned
= 1.9 u + 3.4 u + 3.9 u
= 9.2 u

9.2 u = 174.80
 
1 u = 174.80 ÷ 9.2 = 19

Total number of fruits sold
= 1 u + 2 u + 3 u
= 6 u
= 6 x 19
= 114

Total number of fruits at first
= 114 ÷ ¹₁₂
= 114 x 12
= 1368

Total number of fruits at first
= 9 p + 10 p + 5 p
= 24 p

24 p = 1368

1 p = 1368 ÷ 24 = 57

Number of kiwis that Julie had at first
= 9 p
= 9 x 57
= 513

Answer(s): 513