Usha had some fruits at her stall.
13 of them were mandarin oranges,
14 of the remainder were dragon fruits and the rest were coconuts. The amounts earned for each mandarin orange, each dragon fruit and each coconut sold are $1.90, $1.40 and $1.80 respectively. The number of mandarin oranges sold to the number of dragon fruits sold to the number of coconuts sold was 2 : 4 : 3. In total, she sold
13 of the fruits and earned $207.20. How many coconuts did she have at first?
Mandarin Oranges |
Dragon Fruits |
Coconuts |
Total |
1x2 |
2x2 |
3x2 |
|
1x1 |
3x1 |
|
2 p |
1 p |
3 p |
6 p |
The total number of dragon fruits and coconuts is repeated. Make the total number of dragon fruits and coconuts the same. LCM of 2 and 4 is 4.
|
Mandarin Oranges |
Dragon Fruits |
Coconuts |
Number |
2 u |
4 u |
3 u |
Value |
$1.90 |
$1.40 |
$1.80 |
Total value |
3.8 u |
5.6 u |
5.4 u |
Total amount that Usha earned
= 3.8 u + 5.6 u + 5.4 u
= 14.8 u
14.8 u = 207.20
1 u = 207.20 ÷ 14.8 = 14
Total number of fruits sold
= 2 u + 4 u + 3 u
= 9 u
= 9 x 14
= 126
Total number of fruits at first
= 126 ÷
13= 126 x 3
= 378
Total number of fruits at first
= 2 p + 1 p + 3 p
= 6 p
6 p = 378
1 p = 378 ÷ 6 = 63
Number of coconuts that Usha had at first
= 3 p
= 3 x 63
= 189
Answer(s): 189