Emma had some fruits at her stall. ³₈ of them were apples, ¹₂ of the remainder were apricots and the rest were pomegranates. The amounts earned for each apple, each apricot and each pomegranate sold are $1.80, $1.30 and $1.70 respectively. The number of apples sold to the number of apricots sold to the number of pomegranates sold was 3 : 1 : 3. In total, she sold ¹₈ of the fruits and earned $94.40. How many pomegranates did she have at first?

Apples	Apricots	Pomegranates	Total
3x2	5x2		8x2
	1x5	1x5
6 p	5 p	5 p	16 p

The total number of apricots and pomegranates is repeated.  Make the total number of apricots and pomegranates the same. LCM of 5 and 2 is 10.

	Apples	Apricots	Pomegranates
Number	3 u	1 u	3 u
Value	$1.80	$1.30	$1.70
Total value	5.4 u	1.3 u	5.1 u

Total amount that Emma earned
= 5.4 u + 1.3 u + 5.1 u
= 11.8 u

11.8 u = 94.40
 
1 u = 94.40 ÷ 11.8 = 8

Total number of fruits sold
= 3 u + 1 u + 3 u
= 7 u
= 7 x 8
= 56

Total number of fruits at first
= 56 ÷ ¹₈
= 56 x 8
= 448

Total number of fruits at first
= 6 p + 5 p + 5 p
= 16 p

16 p = 448

1 p = 448 ÷ 16 = 28

Number of pomegranates that Emma had at first
= 5 p
= 5 x 28
= 140

Answer(s): 140