Kimberly had some fruits at her stall.
13 of them were grapefruits,
15 of the remainder were tomatoes and the rest were peaches. The amounts earned for each grapefruit, each tomato and each peach sold are $1.30, $1.50 and $1.10 respectively. The number of grapefruits sold to the number of tomatoes sold to the number of peaches sold was 1 : 3 : 5. In total, she sold
15 of the fruits and earned $180.80. How many grapefruits did she have at first?
Grapefruits |
Tomatoes |
Peaches |
Total |
1x5 |
2x5 |
3x5 |
|
1x2 |
4x2 |
|
5 p |
2 p |
8 p |
15 p |
The total number of tomatoes and peaches is repeated. Make the total number of tomatoes and peaches the same. LCM of 2 and 5 is 10.
|
Grapefruits |
Tomatoes |
Peaches |
Number |
1 u |
3 u |
5 u |
Value |
$1.30 |
$1.50 |
$1.10 |
Total value |
1.3 u |
4.5 u |
5.5 u |
Total amount that Kimberly earned
= 1.3 u + 4.5 u + 5.5 u
= 11.3 u
11.3 u = 180.80
1 u = 180.80 ÷ 11.3 = 16
Total number of fruits sold
= 1 u + 3 u + 5 u
= 9 u
= 9 x 16
= 144
Total number of fruits at first
= 144 ÷
15= 144 x 5
= 720
Total number of fruits at first
= 5 p + 2 p + 8 p
= 15 p
15 p = 720
1 p = 720 ÷ 15 = 48
Number of grapefruits that Kimberly had at first
= 5 p
= 5 x 48
= 240
Answer(s): 240