Shannon had some fruits at her stall.
38 of them were kiwis,
13 of the remainder were grapefruits and the rest were mandarin oranges. The amounts earned for each kiwi, each grapefruit and each mandarin orange sold are $1.30, $1.60 and $1.40 respectively. The number of kiwis sold to the number of grapefruits sold to the number of mandarin oranges sold was 5 : 4 : 2. In total, she sold
112 of the fruits and earned $251.20. How many kiwis did she have at first?
Kiwis |
Grapefruits |
Mandarin Oranges |
Total |
3x3 |
5x3 |
8x3 |
|
1x5 |
2x5 |
|
9 p |
5 p |
10 p |
24 p |
The total number of grapefruits and mandarin oranges is repeated. Make the total number of grapefruits and mandarin oranges the same. LCM of 5 and 3 is 15.
|
Kiwis |
Grapefruits |
Mandarin Oranges |
Number |
5 u |
4 u |
2 u |
Value |
$1.30 |
$1.60 |
$1.40 |
Total value |
6.5 u |
6.4 u |
2.8 u |
Total amount that Shannon earned
= 6.5 u + 6.4 u + 2.8 u
= 15.7 u
15.7 u = 251.20
1 u = 251.20 ÷ 15.7 = 16
Total number of fruits sold
= 5 u + 4 u + 2 u
= 11 u
= 11 x 16
= 176
Total number of fruits at first
= 176 ÷
112= 176 x 12
= 2112
Total number of fruits at first
= 9 p + 5 p + 10 p
= 24 p
24 p = 2112
1 p = 2112 ÷ 24 = 88
Number of kiwis that Shannon had at first
= 9 p
= 9 x 88
= 792
Answer(s): 792