Gem had some fruits at her stall.
13 of them were avocados,
15 of the remainder were kiwis and the rest were peaches. The amounts earned for each avocado, each kiwi and each peach sold are $1.10, $1.90 and $1.30 respectively. The number of avocados sold to the number of kiwis sold to the number of peaches sold was 5 : 2 : 2. In total, she sold
13 of the fruits and earned $178.50. How many avocados did she have at first?
Avocados |
Kiwis |
Peaches |
Total |
1x5 |
2x5 |
3x5 |
|
1x2 |
4x2 |
|
5 p |
2 p |
8 p |
15 p |
The total number of kiwis and peaches is repeated. Make the total number of kiwis and peaches the same. LCM of 2 and 5 is 10.
|
Avocados |
Kiwis |
Peaches |
Number |
5 u |
2 u |
2 u |
Value |
$1.10 |
$1.90 |
$1.30 |
Total value |
5.5 u |
3.8 u |
2.6 u |
Total amount that Gem earned
= 5.5 u + 3.8 u + 2.6 u
= 11.9 u
11.9 u = 178.50
1 u = 178.50 ÷ 11.9 = 15
Total number of fruits sold
= 5 u + 2 u + 2 u
= 9 u
= 9 x 15
= 135
Total number of fruits at first
= 135 ÷
13= 135 x 3
= 405
Total number of fruits at first
= 5 p + 2 p + 8 p
= 15 p
15 p = 405
1 p = 405 ÷ 15 = 27
Number of avocados that Gem had at first
= 5 p
= 5 x 27
= 135
Answer(s): 135