Fiona had some fruits at her stall.
38 of them were apricots,
13 of the remainder were limes and the rest were grapefruits. The amounts earned for each apricot, each lime and each grapefruit sold are $1.50, $1.30 and $1.10 respectively. The number of apricots sold to the number of limes sold to the number of grapefruits sold was 3 : 5 : 1. In total, she sold
18 of the fruits and earned $60.50. How many apricots did she have at first?
Apricots |
Limes |
Grapefruits |
Total |
3x3 |
5x3 |
8x3 |
|
1x5 |
2x5 |
|
9 p |
5 p |
10 p |
24 p |
The total number of limes and grapefruits is repeated. Make the total number of limes and grapefruits the same. LCM of 5 and 3 is 15.
|
Apricots |
Limes |
Grapefruits |
Number |
3 u |
5 u |
1 u |
Value |
$1.50 |
$1.30 |
$1.10 |
Total value |
4.5 u |
6.5 u |
1.1 u |
Total amount that Fiona earned
= 4.5 u + 6.5 u + 1.1 u
= 12.1 u
12.1 u = 60.50
1 u = 60.50 ÷ 12.1 = 5
Total number of fruits sold
= 3 u + 5 u + 1 u
= 9 u
= 9 x 5
= 45
Total number of fruits at first
= 45 ÷
18= 45 x 8
= 360
Total number of fruits at first
= 9 p + 5 p + 10 p
= 24 p
24 p = 360
1 p = 360 ÷ 24 = 15
Number of apricots that Fiona had at first
= 9 p
= 9 x 15
= 135
Answer(s): 135