Dana had some fruits at her stall.
13 of them were coconuts,
14 of the remainder were peaches and the rest were apples. The amounts earned for each coconut, each peach and each apple sold are $1.60, $1.90 and $1.80 respectively. The number of coconuts sold to the number of peaches sold to the number of apples sold was 1 : 2 : 3. In total, she sold
12 of the fruits and earned $97.20. How many apples did she have at first?
Coconuts |
Peaches |
Apples |
Total |
1x2 |
2x2 |
3x2 |
|
1x1 |
3x1 |
|
2 p |
1 p |
3 p |
6 p |
The total number of peaches and apples is repeated. Make the total number of peaches and apples the same. LCM of 2 and 4 is 4.
|
Coconuts |
Peaches |
Apples |
Number |
1 u |
2 u |
3 u |
Value |
$1.60 |
$1.90 |
$1.80 |
Total value |
1.6 u |
3.8 u |
5.4 u |
Total amount that Dana earned
= 1.6 u + 3.8 u + 5.4 u
= 10.8 u
10.8 u = 97.20
1 u = 97.20 ÷ 10.8 = 9
Total number of fruits sold
= 1 u + 2 u + 3 u
= 6 u
= 6 x 9
= 54
Total number of fruits at first
= 54 ÷
12= 54 x 2
= 108
Total number of fruits at first
= 2 p + 1 p + 3 p
= 6 p
6 p = 108
1 p = 108 ÷ 6 = 18
Number of apples that Dana had at first
= 3 p
= 3 x 18
= 54
Answer(s): 54