Yen had some fruits at her stall.
38 of them were mandarin oranges,
13 of the remainder were avocados and the rest were oranges. The amounts earned for each mandarin orange, each avocado and each orange sold are $1.50, $1.10 and $1.40 respectively. The number of mandarin oranges sold to the number of avocados sold to the number of oranges sold was 1 : 3 : 4. In total, she sold
18 of the fruits and earned $124.80. How many oranges did she have at first?
Mandarin Oranges |
Avocados |
Oranges |
Total |
3x3 |
5x3 |
8x3 |
|
1x5 |
2x5 |
|
9 p |
5 p |
10 p |
24 p |
The total number of avocados and oranges is repeated. Make the total number of avocados and oranges the same. LCM of 5 and 3 is 15.
|
Mandarin Oranges |
Avocados |
Oranges |
Number |
1 u |
3 u |
4 u |
Value |
$1.50 |
$1.10 |
$1.40 |
Total value |
1.5 u |
3.3 u |
5.6 u |
Total amount that Yen earned
= 1.5 u + 3.3 u + 5.6 u
= 10.4 u
10.4 u = 124.80
1 u = 124.80 ÷ 10.4 = 12
Total number of fruits sold
= 1 u + 3 u + 4 u
= 8 u
= 8 x 12
= 96
Total number of fruits at first
= 96 ÷
18= 96 x 8
= 768
Total number of fruits at first
= 9 p + 5 p + 10 p
= 24 p
24 p = 768
1 p = 768 ÷ 24 = 32
Number of oranges that Yen had at first
= 10 p
= 10 x 32
= 320
Answer(s): 320