Fanny had some fruits at her stall.
13 of them were mandarin oranges,
34 of the remainder were dates and the rest were grapefruits. The amounts earned for each mandarin orange, each date and each grapefruit sold are $1.80, $1.40 and $1.10 respectively. The number of mandarin oranges sold to the number of dates sold to the number of grapefruits sold was 3 : 4 : 1. In total, she sold
13 of the fruits and earned $193.60. How many mandarin oranges did she have at first?
Mandarin Oranges |
Dates |
Grapefruits |
Total |
1x2 |
2x2 |
3x2 |
|
3x1 |
1x1 |
|
2 p |
3 p |
1 p |
6 p |
The total number of dates and grapefruits is repeated. Make the total number of dates and grapefruits the same. LCM of 2 and 4 is 4.
|
Mandarin Oranges |
Dates |
Grapefruits |
Number |
3 u |
4 u |
1 u |
Value |
$1.80 |
$1.40 |
$1.10 |
Total value |
5.4 u |
5.6 u |
1.1 u |
Total amount that Fanny earned
= 5.4 u + 5.6 u + 1.1 u
= 12.1 u
12.1 u = 193.60
1 u = 193.60 ÷ 12.1 = 16
Total number of fruits sold
= 3 u + 4 u + 1 u
= 8 u
= 8 x 16
= 128
Total number of fruits at first
= 128 ÷
13= 128 x 3
= 384
Total number of fruits at first
= 2 p + 3 p + 1 p
= 6 p
6 p = 384
1 p = 384 ÷ 6 = 64
Number of mandarin oranges that Fanny had at first
= 2 p
= 2 x 64
= 128
Answer(s): 128