Wendy had some fruits at her stall.
38 of them were peaches,
14 of the remainder were apricots and the rest were grapefruits. The amounts earned for each peach, each apricot and each grapefruit sold are $1.50, $1.80 and $1.10 respectively. The number of peaches sold to the number of apricots sold to the number of grapefruits sold was 1 : 3 : 2. In total, she sold
18 of the fruits and earned $72.80. How many peaches did she have at first?
Peaches |
Apricots |
Grapefruits |
Total |
3x4 |
5x4 |
8x4 |
|
1x5 |
3x5 |
|
12 p |
5 p |
15 p |
32 p |
The total number of apricots and grapefruits is repeated. Make the total number of apricots and grapefruits the same. LCM of 5 and 4 is 20.
|
Peaches |
Apricots |
Grapefruits |
Number |
1 u |
3 u |
2 u |
Value |
$1.50 |
$1.80 |
$1.10 |
Total value |
1.5 u |
5.4 u |
2.2 u |
Total amount that Wendy earned
= 1.5 u + 5.4 u + 2.2 u
= 9.1 u
9.1 u = 72.80
1 u = 72.80 ÷ 9.1 = 8
Total number of fruits sold
= 1 u + 3 u + 2 u
= 6 u
= 6 x 8
= 48
Total number of fruits at first
= 48 ÷
18= 48 x 8
= 384
Total number of fruits at first
= 12 p + 5 p + 15 p
= 32 p
32 p = 384
1 p = 384 ÷ 32 = 12
Number of peaches that Wendy had at first
= 12 p
= 12 x 12
= 144
Answer(s): 144