Xandra had some fruits at her stall.
13 of them were apricots,
34 of the remainder were guavas and the rest were pears. The amounts earned for each apricot, each guava and each pear sold are $1.10, $1.20 and $1.70 respectively. The number of apricots sold to the number of guavas sold to the number of pears sold was 4 : 3 : 2. In total, she sold
12 of the fruits and earned $34.20. How many apricots did she have at first?
Apricots |
Guavas |
Pears |
Total |
1x2 |
2x2 |
3x2 |
|
3x1 |
1x1 |
|
2 p |
3 p |
1 p |
6 p |
The total number of guavas and pears is repeated. Make the total number of guavas and pears the same. LCM of 2 and 4 is 4.
|
Apricots |
Guavas |
Pears |
Number |
4 u |
3 u |
2 u |
Value |
$1.10 |
$1.20 |
$1.70 |
Total value |
4.4 u |
3.6 u |
3.4 u |
Total amount that Xandra earned
= 4.4 u + 3.6 u + 3.4 u
= 11.4 u
11.4 u = 34.20
1 u = 34.20 ÷ 11.4 = 3
Total number of fruits sold
= 4 u + 3 u + 2 u
= 9 u
= 9 x 3
= 27
Total number of fruits at first
= 27 ÷
12= 27 x 2
= 54
Total number of fruits at first
= 2 p + 3 p + 1 p
= 6 p
6 p = 54
1 p = 54 ÷ 6 = 9
Number of apricots that Xandra had at first
= 2 p
= 2 x 9
= 18
Answer(s): 18