Yen had some fruits at her stall.
13 of them were avocados,
15 of the remainder were mandarin oranges and the rest were pears. The amounts earned for each avocado, each mandarin orange and each pear sold are $1.50, $1.80 and $1.60 respectively. The number of avocados sold to the number of mandarin oranges sold to the number of pears sold was 1 : 2 : 2. In total, she sold
15 of the fruits and earned $74.70. How many avocados did she have at first?
Avocados |
Mandarin Oranges |
Pears |
Total |
1x5 |
2x5 |
3x5 |
|
1x2 |
4x2 |
|
5 p |
2 p |
8 p |
15 p |
The total number of mandarin oranges and pears is repeated. Make the total number of mandarin oranges and pears the same. LCM of 2 and 5 is 10.
|
Avocados |
Mandarin Oranges |
Pears |
Number |
1 u |
2 u |
2 u |
Value |
$1.50 |
$1.80 |
$1.60 |
Total value |
1.5 u |
3.6 u |
3.2 u |
Total amount that Yen earned
= 1.5 u + 3.6 u + 3.2 u
= 8.3 u
8.3 u = 74.70
1 u = 74.70 ÷ 8.3 = 9
Total number of fruits sold
= 1 u + 2 u + 2 u
= 5 u
= 5 x 9
= 45
Total number of fruits at first
= 45 ÷
15= 45 x 5
= 225
Total number of fruits at first
= 5 p + 2 p + 8 p
= 15 p
15 p = 225
1 p = 225 ÷ 15 = 15
Number of avocados that Yen had at first
= 5 p
= 5 x 15
= 75
Answer(s): 75