Esther had some fruits at her stall.
38 of them were avocados,
13 of the remainder were peaches and the rest were grapefruits. The amounts earned for each avocado, each peach and each grapefruit sold are $1.30, $1.60 and $1.40 respectively. The number of avocados sold to the number of peaches sold to the number of grapefruits sold was 1 : 4 : 3. In total, she sold
112 of the fruits and earned $154.70. How many avocados did she have at first?
Avocados |
Peaches |
Grapefruits |
Total |
3x3 |
5x3 |
8x3 |
|
1x5 |
2x5 |
|
9 p |
5 p |
10 p |
24 p |
The total number of peaches and grapefruits is repeated. Make the total number of peaches and grapefruits the same. LCM of 5 and 3 is 15.
|
Avocados |
Peaches |
Grapefruits |
Number |
1 u |
4 u |
3 u |
Value |
$1.30 |
$1.60 |
$1.40 |
Total value |
1.3 u |
6.4 u |
4.2 u |
Total amount that Esther earned
= 1.3 u + 6.4 u + 4.2 u
= 11.9 u
11.9 u = 154.70
1 u = 154.70 ÷ 11.9 = 13
Total number of fruits sold
= 1 u + 4 u + 3 u
= 8 u
= 8 x 13
= 104
Total number of fruits at first
= 104 ÷
112= 104 x 12
= 1248
Total number of fruits at first
= 9 p + 5 p + 10 p
= 24 p
24 p = 1248
1 p = 1248 ÷ 24 = 52
Number of avocados that Esther had at first
= 9 p
= 9 x 52
= 468
Answer(s): 468