Risa had some fruits at her stall.
38 of them were peaches,
14 of the remainder were kiwis and the rest were limes. The amounts earned for each peach, each kiwi and each lime sold are $1.20, $1.60 and $1.90 respectively. The number of peaches sold to the number of kiwis sold to the number of limes sold was 3 : 3 : 1. In total, she sold
18 of the fruits and earned $41.20. How many peaches did she have at first?
Peaches |
Kiwis |
Limes |
Total |
3x4 |
5x4 |
8x4 |
|
1x5 |
3x5 |
|
12 p |
5 p |
15 p |
32 p |
The total number of kiwis and limes is repeated. Make the total number of kiwis and limes the same. LCM of 5 and 4 is 20.
|
Peaches |
Kiwis |
Limes |
Number |
3 u |
3 u |
1 u |
Value |
$1.20 |
$1.60 |
$1.90 |
Total value |
3.6 u |
4.8 u |
1.9 u |
Total amount that Risa earned
= 3.6 u + 4.8 u + 1.9 u
= 10.3 u
10.3 u = 41.20
1 u = 41.20 ÷ 10.3 = 4
Total number of fruits sold
= 3 u + 3 u + 1 u
= 7 u
= 7 x 4
= 28
Total number of fruits at first
= 28 ÷
18= 28 x 8
= 224
Total number of fruits at first
= 12 p + 5 p + 15 p
= 32 p
32 p = 224
1 p = 224 ÷ 32 = 7
Number of peaches that Risa had at first
= 12 p
= 12 x 7
= 84
Answer(s): 84