Dana had some fruits at her stall.
13 of them were kiwis,
14 of the remainder were tomatoes and the rest were guavas. The amounts earned for each kiwi, each tomato and each guava sold are $1.90, $1.40 and $1.70 respectively. The number of kiwis sold to the number of tomatoes sold to the number of guavas sold was 5 : 1 : 2. In total, she sold
13 of the fruits and earned $100.10. How many guavas did she have at first?
Kiwis |
Tomatoes |
Guavas |
Total |
1x2 |
2x2 |
3x2 |
|
1x1 |
3x1 |
|
2 p |
1 p |
3 p |
6 p |
The total number of tomatoes and guavas is repeated. Make the total number of tomatoes and guavas the same. LCM of 2 and 4 is 4.
|
Kiwis |
Tomatoes |
Guavas |
Number |
5 u |
1 u |
2 u |
Value |
$1.90 |
$1.40 |
$1.70 |
Total value |
9.5 u |
1.4 u |
3.4 u |
Total amount that Dana earned
= 9.5 u + 1.4 u + 3.4 u
= 14.3 u
14.3 u = 100.10
1 u = 100.10 ÷ 14.3 = 7
Total number of fruits sold
= 5 u + 1 u + 2 u
= 8 u
= 8 x 7
= 56
Total number of fruits at first
= 56 ÷
13= 56 x 3
= 168
Total number of fruits at first
= 2 p + 1 p + 3 p
= 6 p
6 p = 168
1 p = 168 ÷ 6 = 28
Number of guavas that Dana had at first
= 3 p
= 3 x 28
= 84
Answer(s): 84