Joelle had some fruits at her stall.
38 of them were dragon fruits,
23 of the remainder were apricots and the rest were plums. The amounts earned for each dragon fruit, each apricot and each plum sold are $1.30, $1.10 and $1.60 respectively. The number of dragon fruits sold to the number of apricots sold to the number of plums sold was 4 : 4 : 1. In total, she sold
18 of the fruits and earned $89.60. How many plums did she have at first?
Dragon Fruits |
Apricots |
Plums |
Total |
3x3 |
5x3 |
8x3 |
|
2x5 |
1x5 |
|
9 p |
10 p |
5 p |
24 p |
The total number of apricots and plums is repeated. Make the total number of apricots and plums the same. LCM of 5 and 3 is 15.
|
Dragon Fruits |
Apricots |
Plums |
Number |
4 u |
4 u |
1 u |
Value |
$1.30 |
$1.10 |
$1.60 |
Total value |
5.2 u |
4.4 u |
1.6 u |
Total amount that Joelle earned
= 5.2 u + 4.4 u + 1.6 u
= 11.2 u
11.2 u = 89.60
1 u = 89.60 ÷ 11.2 = 8
Total number of fruits sold
= 4 u + 4 u + 1 u
= 9 u
= 9 x 8
= 72
Total number of fruits at first
= 72 ÷
18= 72 x 8
= 576
Total number of fruits at first
= 9 p + 10 p + 5 p
= 24 p
24 p = 576
1 p = 576 ÷ 24 = 24
Number of plums that Joelle had at first
= 5 p
= 5 x 24
= 120
Answer(s): 120