Dana had some fruits at her stall. ¹₃ of them were coconuts, ¹₄ of the remainder were papayas and the rest were kiwis. The amounts earned for each coconut, each papaya and each kiwi sold are $1.80, $1.20 and $1.70 respectively. The number of coconuts sold to the number of papayas sold to the number of kiwis sold was 4 : 3 : 2. In total, she sold ¹₃ of the fruits and earned $28.40. How many kiwis did she have at first?

Coconuts	Papayas	Kiwis	Total
1x2	2x2		3x2
	1x1	3x1
2 p	1 p	3 p	6 p

The total number of papayas and kiwis is repeated.  Make the total number of papayas and kiwis the same. LCM of 2 and 4 is 4.

	Coconuts	Papayas	Kiwis
Number	4 u	3 u	2 u
Value	$1.80	$1.20	$1.70
Total value	7.2 u	3.6 u	3.4 u

Total amount that Dana earned
= 7.2 u + 3.6 u + 3.4 u
= 14.2 u

14.2 u = 28.40
 
1 u = 28.40 ÷ 14.2 = 2

Total number of fruits sold
= 4 u + 3 u + 2 u
= 9 u
= 9 x 2
= 18

Total number of fruits at first
= 18 ÷ ¹₃
= 18 x 3
= 54

Total number of fruits at first
= 2 p + 1 p + 3 p
= 6 p

6 p = 54

1 p = 54 ÷ 6 = 9

Number of kiwis that Dana had at first
= 3 p
= 3 x 9
= 27

Answer(s): 27