Tammy had some fruits at her stall.
38 of them were pomegranates,
13 of the remainder were guavas and the rest were pears. The amounts earned for each pomegranate, each guava and each pear sold are $1.70, $1.80 and $1.20 respectively. The number of pomegranates sold to the number of guavas sold to the number of pears sold was 1 : 3 : 3. In total, she sold
18 of the fruits and earned $64.20. How many pomegranates did she have at first?
Pomegranates |
Guavas |
Pears |
Total |
3x3 |
5x3 |
8x3 |
|
1x5 |
2x5 |
|
9 p |
5 p |
10 p |
24 p |
The total number of guavas and pears is repeated. Make the total number of guavas and pears the same. LCM of 5 and 3 is 15.
|
Pomegranates |
Guavas |
Pears |
Number |
1 u |
3 u |
3 u |
Value |
$1.70 |
$1.80 |
$1.20 |
Total value |
1.7 u |
5.4 u |
3.6 u |
Total amount that Tammy earned
= 1.7 u + 5.4 u + 3.6 u
= 10.7 u
10.7 u = 64.20
1 u = 64.20 ÷ 10.7 = 6
Total number of fruits sold
= 1 u + 3 u + 3 u
= 7 u
= 7 x 6
= 42
Total number of fruits at first
= 42 ÷
18= 42 x 8
= 336
Total number of fruits at first
= 9 p + 5 p + 10 p
= 24 p
24 p = 336
1 p = 336 ÷ 24 = 14
Number of pomegranates that Tammy had at first
= 9 p
= 9 x 14
= 126
Answer(s): 126