Xuan had some fruits at her stall.
13 of them were kiwis,
34 of the remainder were plums and the rest were avocados. The amounts earned for each kiwi, each plum and each avocado sold are $1.40, $1.60 and $1.90 respectively. The number of kiwis sold to the number of plums sold to the number of avocados sold was 3 : 4 : 5. In total, she sold
13 of the fruits and earned $180.90. How many kiwis did she have at first?
Kiwis |
Plums |
Avocados |
Total |
1x2 |
2x2 |
3x2 |
|
3x1 |
1x1 |
|
2 p |
3 p |
1 p |
6 p |
The total number of plums and avocados is repeated. Make the total number of plums and avocados the same. LCM of 2 and 4 is 4.
|
Kiwis |
Plums |
Avocados |
Number |
3 u |
4 u |
5 u |
Value |
$1.40 |
$1.60 |
$1.90 |
Total value |
4.2 u |
6.4 u |
9.5 u |
Total amount that Xuan earned
= 4.2 u + 6.4 u + 9.5 u
= 20.1 u
20.1 u = 180.90
1 u = 180.90 ÷ 20.1 = 9
Total number of fruits sold
= 3 u + 4 u + 5 u
= 12 u
= 12 x 9
= 108
Total number of fruits at first
= 108 ÷
13= 108 x 3
= 324
Total number of fruits at first
= 2 p + 3 p + 1 p
= 6 p
6 p = 324
1 p = 324 ÷ 6 = 54
Number of kiwis that Xuan had at first
= 2 p
= 2 x 54
= 108
Answer(s): 108