Fiona had some fruits at her stall.
13 of them were plums,
13 of the remainder were lemons and the rest were pomegranates. The amounts earned for each plum, each lemon and each pomegranate sold are $1.20, $1.90 and $1.10 respectively. The number of plums sold to the number of lemons sold to the number of pomegranates sold was 4 : 3 : 3. In total, she sold
13 of the fruits and earned $165.60. How many pomegranates did she have at first?
Plums |
Lemons |
Pomegranates |
Total |
1x3 |
2x3 |
3x3 |
|
1x2 |
2x2 |
|
3 p |
2 p |
4 p |
9 p |
The total number of lemons and pomegranates is repeated. Make the total number of lemons and pomegranates the same. LCM of 2 and 3 is 6.
|
Plums |
Lemons |
Pomegranates |
Number |
4 u |
3 u |
3 u |
Value |
$1.20 |
$1.90 |
$1.10 |
Total value |
4.8 u |
5.7 u |
3.3 u |
Total amount that Fiona earned
= 4.8 u + 5.7 u + 3.3 u
= 13.8 u
13.8 u = 165.60
1 u = 165.60 ÷ 13.8 = 12
Total number of fruits sold
= 4 u + 3 u + 3 u
= 10 u
= 10 x 12
= 120
Total number of fruits at first
= 120 ÷
13= 120 x 3
= 360
Total number of fruits at first
= 3 p + 2 p + 4 p
= 9 p
9 p = 360
1 p = 360 ÷ 9 = 40
Number of pomegranates that Fiona had at first
= 4 p
= 4 x 40
= 160
Answer(s): 160