Yen had some fruits at her stall. ³₈ of them were oranges, ²₃ of the remainder were peaches and the rest were apricots. The amounts earned for each orange, each peach and each apricot sold are $1.20, $1.60 and $1.40 respectively. The number of oranges sold to the number of peaches sold to the number of apricots sold was 1 : 1 : 1. In total, she sold ¹₆ of the fruits and earned $16.80. How many apricots did she have at first?

Oranges	Peaches	Apricots	Total
3x3	5x3		8x3
	2x5	1x5
9 p	10 p	5 p	24 p

The total number of peaches and apricots is repeated.  Make the total number of peaches and apricots the same. LCM of 5 and 3 is 15.

	Oranges	Peaches	Apricots
Number	1 u	1 u	1 u
Value	$1.20	$1.60	$1.40
Total value	1.2 u	1.6 u	1.4 u

Total amount that Yen earned
= 1.2 u + 1.6 u + 1.4 u
= 4.2 u

4.2 u = 16.80
 
1 u = 16.80 ÷ 4.2 = 4

Total number of fruits sold
= 1 u + 1 u + 1 u
= 3 u
= 3 x 4
= 12

Total number of fruits at first
= 12 ÷ ¹₆
= 12 x 6
= 72

Total number of fruits at first
= 9 p + 10 p + 5 p
= 24 p

24 p = 72

1 p = 72 ÷ 24 = 3

Number of apricots that Yen had at first
= 5 p
= 5 x 3
= 15

Answer(s): 15