Ivory had some fruits at her stall.
38 of them were peaches,
34 of the remainder were mandarin oranges and the rest were apples. The amounts earned for each peach, each mandarin orange and each apple sold are $1.50, $1.90 and $1.60 respectively. The number of peaches sold to the number of mandarin oranges sold to the number of apples sold was 3 : 4 : 3. In total, she sold
116 of the fruits and earned $152.10. How many apples did she have at first?
Peaches |
Mandarin Oranges |
Apples |
Total |
3x4 |
5x4 |
8x4 |
|
3x5 |
1x5 |
|
12 p |
15 p |
5 p |
32 p |
The total number of mandarin oranges and apples is repeated. Make the total number of mandarin oranges and apples the same. LCM of 5 and 4 is 20.
|
Peaches |
Mandarin Oranges |
Apples |
Number |
3 u |
4 u |
3 u |
Value |
$1.50 |
$1.90 |
$1.60 |
Total value |
4.5 u |
7.6 u |
4.8 u |
Total amount that Ivory earned
= 4.5 u + 7.6 u + 4.8 u
= 16.9 u
16.9 u = 152.10
1 u = 152.10 ÷ 16.9 = 9
Total number of fruits sold
= 3 u + 4 u + 3 u
= 10 u
= 10 x 9
= 90
Total number of fruits at first
= 90 ÷
116= 90 x 16
= 1440
Total number of fruits at first
= 12 p + 15 p + 5 p
= 32 p
32 p = 1440
1 p = 1440 ÷ 32 = 45
Number of apples that Ivory had at first
= 5 p
= 5 x 45
= 225
Answer(s): 225