Olivia had some fruits at her stall.
38 of them were peaches,
13 of the remainder were grapefruits and the rest were mandarin oranges. The amounts earned for each peach, each grapefruit and each mandarin orange sold are $1.30, $1.20 and $1.90 respectively. The number of peaches sold to the number of grapefruits sold to the number of mandarin oranges sold was 2 : 3 : 1. In total, she sold
18 of the fruits and earned $137.70. How many mandarin oranges did she have at first?
Peaches |
Grapefruits |
Mandarin Oranges |
Total |
3x3 |
5x3 |
8x3 |
|
1x5 |
2x5 |
|
9 p |
5 p |
10 p |
24 p |
The total number of grapefruits and mandarin oranges is repeated. Make the total number of grapefruits and mandarin oranges the same. LCM of 5 and 3 is 15.
|
Peaches |
Grapefruits |
Mandarin Oranges |
Number |
2 u |
3 u |
1 u |
Value |
$1.30 |
$1.20 |
$1.90 |
Total value |
2.6 u |
3.6 u |
1.9 u |
Total amount that Olivia earned
= 2.6 u + 3.6 u + 1.9 u
= 8.1 u
8.1 u = 137.70
1 u = 137.70 ÷ 8.1 = 17
Total number of fruits sold
= 2 u + 3 u + 1 u
= 6 u
= 6 x 17
= 102
Total number of fruits at first
= 102 ÷
18= 102 x 8
= 816
Total number of fruits at first
= 9 p + 5 p + 10 p
= 24 p
24 p = 816
1 p = 816 ÷ 24 = 34
Number of mandarin oranges that Olivia had at first
= 10 p
= 10 x 34
= 340
Answer(s): 340