Jane had some fruits at her stall.
13 of them were limes,
34 of the remainder were mangosteens and the rest were guavas. The amounts earned for each lime, each mangosteen and each guava sold are $1.90, $1.80 and $1.20 respectively. The number of limes sold to the number of mangosteens sold to the number of guavas sold was 4 : 1 : 1. In total, she sold
13 of the fruits and earned $95.40. How many limes did she have at first?
Limes |
Mangosteens |
Guavas |
Total |
1x2 |
2x2 |
3x2 |
|
3x1 |
1x1 |
|
2 p |
3 p |
1 p |
6 p |
The total number of mangosteens and guavas is repeated. Make the total number of mangosteens and guavas the same. LCM of 2 and 4 is 4.
|
Limes |
Mangosteens |
Guavas |
Number |
4 u |
1 u |
1 u |
Value |
$1.90 |
$1.80 |
$1.20 |
Total value |
7.6 u |
1.8 u |
1.2 u |
Total amount that Jane earned
= 7.6 u + 1.8 u + 1.2 u
= 10.6 u
10.6 u = 95.40
1 u = 95.40 ÷ 10.6 = 9
Total number of fruits sold
= 4 u + 1 u + 1 u
= 6 u
= 6 x 9
= 54
Total number of fruits at first
= 54 ÷
13= 54 x 3
= 162
Total number of fruits at first
= 2 p + 3 p + 1 p
= 6 p
6 p = 162
1 p = 162 ÷ 6 = 27
Number of limes that Jane had at first
= 2 p
= 2 x 27
= 54
Answer(s): 54