Cindy had some fruits at her stall.
38 of them were apricots,
34 of the remainder were avocados and the rest were mandarin oranges. The amounts earned for each apricot, each avocado and each mandarin orange sold are $1.70, $1.60 and $1.20 respectively. The number of apricots sold to the number of avocados sold to the number of mandarin oranges sold was 3 : 4 : 1. In total, she sold
116 of the fruits and earned $101.60. How many mandarin oranges did she have at first?
Apricots |
Avocados |
Mandarin Oranges |
Total |
3x4 |
5x4 |
8x4 |
|
3x5 |
1x5 |
|
12 p |
15 p |
5 p |
32 p |
The total number of avocados and mandarin oranges is repeated. Make the total number of avocados and mandarin oranges the same. LCM of 5 and 4 is 20.
|
Apricots |
Avocados |
Mandarin Oranges |
Number |
3 u |
4 u |
1 u |
Value |
$1.70 |
$1.60 |
$1.20 |
Total value |
5.1 u |
6.4 u |
1.2 u |
Total amount that Cindy earned
= 5.1 u + 6.4 u + 1.2 u
= 12.7 u
12.7 u = 101.60
1 u = 101.60 ÷ 12.7 = 8
Total number of fruits sold
= 3 u + 4 u + 1 u
= 8 u
= 8 x 8
= 64
Total number of fruits at first
= 64 ÷
116= 64 x 16
= 1024
Total number of fruits at first
= 12 p + 15 p + 5 p
= 32 p
32 p = 1024
1 p = 1024 ÷ 32 = 32
Number of mandarin oranges that Cindy had at first
= 5 p
= 5 x 32
= 160
Answer(s): 160