Emma had some fruits at her stall.
38 of them were peaches,
13 of the remainder were pomegranates and the rest were dates. The amounts earned for each peach, each pomegranate and each date sold are $1.90, $1.40 and $1.60 respectively. The number of peaches sold to the number of pomegranates sold to the number of dates sold was 2 : 3 : 4. In total, she sold
14 of the fruits and earned $57.60. How many peaches did she have at first?
Peaches |
Pomegranates |
Dates |
Total |
3x3 |
5x3 |
8x3 |
|
1x5 |
2x5 |
|
9 p |
5 p |
10 p |
24 p |
The total number of pomegranates and dates is repeated. Make the total number of pomegranates and dates the same. LCM of 5 and 3 is 15.
|
Peaches |
Pomegranates |
Dates |
Number |
2 u |
3 u |
4 u |
Value |
$1.90 |
$1.40 |
$1.60 |
Total value |
3.8 u |
4.2 u |
6.4 u |
Total amount that Emma earned
= 3.8 u + 4.2 u + 6.4 u
= 14.4 u
14.4 u = 57.60
1 u = 57.60 ÷ 14.4 = 4
Total number of fruits sold
= 2 u + 3 u + 4 u
= 9 u
= 9 x 4
= 36
Total number of fruits at first
= 36 ÷
14= 36 x 4
= 144
Total number of fruits at first
= 9 p + 5 p + 10 p
= 24 p
24 p = 144
1 p = 144 ÷ 24 = 6
Number of peaches that Emma had at first
= 9 p
= 9 x 6
= 54
Answer(s): 54