Min had some fruits at her stall. ³₈ of them were kiwis, ³₄ of the remainder were lemons and the rest were papayas. The amounts earned for each kiwi, each lemon and each papaya sold are $1.60, $1.50 and $1.70 respectively. The number of kiwis sold to the number of lemons sold to the number of papayas sold was 2 : 3 : 2. In total, she sold ¹₈ of the fruits and earned $177.60. How many papayas did she have at first?

Kiwis	Lemons	Papayas	Total
3x4	5x4		8x4
	3x5	1x5
12 p	15 p	5 p	32 p

The total number of lemons and papayas is repeated.  Make the total number of lemons and papayas the same. LCM of 5 and 4 is 20.

	Kiwis	Lemons	Papayas
Number	2 u	3 u	2 u
Value	$1.60	$1.50	$1.70
Total value	3.2 u	4.5 u	3.4 u

Total amount that Min earned
= 3.2 u + 4.5 u + 3.4 u
= 11.1 u

11.1 u = 177.60
 
1 u = 177.60 ÷ 11.1 = 16

Total number of fruits sold
= 2 u + 3 u + 2 u
= 7 u
= 7 x 16
= 112

Total number of fruits at first
= 112 ÷ ¹₈
= 112 x 8
= 896

Total number of fruits at first
= 12 p + 15 p + 5 p
= 32 p

32 p = 896

1 p = 896 ÷ 32 = 28

Number of papayas that Min had at first
= 5 p
= 5 x 28
= 140

Answer(s): 140