Tina had some fruits at her stall.
38 of them were dates,
34 of the remainder were peaches and the rest were pears. The amounts earned for each date, each peach and each pear sold are $1.60, $1.90 and $1.50 respectively. The number of dates sold to the number of peaches sold to the number of pears sold was 1 : 2 : 1. In total, she sold
116 of the fruits and earned $96.60. How many pears did she have at first?
Dates |
Peaches |
Pears |
Total |
3x4 |
5x4 |
8x4 |
|
3x5 |
1x5 |
|
12 p |
15 p |
5 p |
32 p |
The total number of peaches and pears is repeated. Make the total number of peaches and pears the same. LCM of 5 and 4 is 20.
|
Dates |
Peaches |
Pears |
Number |
1 u |
2 u |
1 u |
Value |
$1.60 |
$1.90 |
$1.50 |
Total value |
1.6 u |
3.8 u |
1.5 u |
Total amount that Tina earned
= 1.6 u + 3.8 u + 1.5 u
= 6.9 u
6.9 u = 96.60
1 u = 96.60 ÷ 6.9 = 14
Total number of fruits sold
= 1 u + 2 u + 1 u
= 4 u
= 4 x 14
= 56
Total number of fruits at first
= 56 ÷
116= 56 x 16
= 896
Total number of fruits at first
= 12 p + 15 p + 5 p
= 32 p
32 p = 896
1 p = 896 ÷ 32 = 28
Number of pears that Tina had at first
= 5 p
= 5 x 28
= 140
Answer(s): 140