Jean had some fruits at her stall. ¹₃ of them were apricots, ²₃ of the remainder were mandarin oranges and the rest were tomatoes. The amounts earned for each apricot, each mandarin orange and each tomato sold are $1.20, $1.90 and $1.40 respectively. The number of apricots sold to the number of mandarin oranges sold to the number of tomatoes sold was 4 : 5 : 3. In total, she sold ¹₃ of the fruits and earned $203.50. How many apricots did she have at first?

Apricots	Mandarin Oranges	Tomatoes	Total
1x3	2x3		3x3
	2x2	1x2
3 p	4 p	2 p	9 p

The total number of mandarin oranges and tomatoes is repeated.  Make the total number of mandarin oranges and tomatoes the same. LCM of 2 and 3 is 6.

	Apricots	Mandarin Oranges	Tomatoes
Number	4 u	5 u	3 u
Value	$1.20	$1.90	$1.40
Total value	4.8 u	9.5 u	4.2 u

Total amount that Jean earned
= 4.8 u + 9.5 u + 4.2 u
= 18.5 u

18.5 u = 203.50
 
1 u = 203.50 ÷ 18.5 = 11

Total number of fruits sold
= 4 u + 5 u + 3 u
= 12 u
= 12 x 11
= 132

Total number of fruits at first
= 132 ÷ ¹₃
= 132 x 3
= 396

Total number of fruits at first
= 3 p + 4 p + 2 p
= 9 p

9 p = 396

1 p = 396 ÷ 9 = 44

Number of apricots that Jean had at first
= 3 p
= 3 x 44
= 132

Answer(s): 132