Hilda had some fruits at her stall.
38 of them were apricots,
14 of the remainder were grapefruits and the rest were dragon fruits. The amounts earned for each apricot, each grapefruit and each dragon fruit sold are $1.50, $1.60 and $1.30 respectively. The number of apricots sold to the number of grapefruits sold to the number of dragon fruits sold was 1 : 1 : 4. In total, she sold
116 of the fruits and earned $149.40. How many dragon fruits did she have at first?
Apricots |
Grapefruits |
Dragon Fruits |
Total |
3x4 |
5x4 |
8x4 |
|
1x5 |
3x5 |
|
12 p |
5 p |
15 p |
32 p |
The total number of grapefruits and dragon fruits is repeated. Make the total number of grapefruits and dragon fruits the same. LCM of 5 and 4 is 20.
|
Apricots |
Grapefruits |
Dragon Fruits |
Number |
1 u |
1 u |
4 u |
Value |
$1.50 |
$1.60 |
$1.30 |
Total value |
1.5 u |
1.6 u |
5.2 u |
Total amount that Hilda earned
= 1.5 u + 1.6 u + 5.2 u
= 8.3 u
8.3 u = 149.40
1 u = 149.40 ÷ 8.3 = 18
Total number of fruits sold
= 1 u + 1 u + 4 u
= 6 u
= 6 x 18
= 108
Total number of fruits at first
= 108 ÷
116= 108 x 16
= 1728
Total number of fruits at first
= 12 p + 5 p + 15 p
= 32 p
32 p = 1728
1 p = 1728 ÷ 32 = 54
Number of dragon fruits that Hilda had at first
= 15 p
= 15 x 54
= 810
Answer(s): 810