Jean had some fruits at her stall.
38 of them were apples,
23 of the remainder were dates and the rest were tomatoes. The amounts earned for each apple, each date and each tomato sold are $1.10, $1.60 and $1.70 respectively. The number of apples sold to the number of dates sold to the number of tomatoes sold was 5 : 3 : 4. In total, she sold
14 of the fruits and earned $273.60. How many tomatoes did she have at first?
Apples |
Dates |
Tomatoes |
Total |
3x3 |
5x3 |
8x3 |
|
2x5 |
1x5 |
|
9 p |
10 p |
5 p |
24 p |
The total number of dates and tomatoes is repeated. Make the total number of dates and tomatoes the same. LCM of 5 and 3 is 15.
|
Apples |
Dates |
Tomatoes |
Number |
5 u |
3 u |
4 u |
Value |
$1.10 |
$1.60 |
$1.70 |
Total value |
5.5 u |
4.8 u |
6.8 u |
Total amount that Jean earned
= 5.5 u + 4.8 u + 6.8 u
= 17.1 u
17.1 u = 273.60
1 u = 273.60 ÷ 17.1 = 16
Total number of fruits sold
= 5 u + 3 u + 4 u
= 12 u
= 12 x 16
= 192
Total number of fruits at first
= 192 ÷
14= 192 x 4
= 768
Total number of fruits at first
= 9 p + 10 p + 5 p
= 24 p
24 p = 768
1 p = 768 ÷ 24 = 32
Number of tomatoes that Jean had at first
= 5 p
= 5 x 32
= 160
Answer(s): 160