Roshel had some fruits at her stall.
38 of them were tomatoes,
12 of the remainder were mangosteens and the rest were apples. The amounts earned for each tomato, each mangosteen and each apple sold are $1.70, $1.90 and $1.50 respectively. The number of tomatoes sold to the number of mangosteens sold to the number of apples sold was 1 : 4 : 1. In total, she sold
14 of the fruits and earned $151.20. How many apples did she have at first?
Tomatoes |
Mangosteens |
Apples |
Total |
3x2 |
5x2 |
8x2 |
|
1x5 |
1x5 |
|
6 p |
5 p |
5 p |
16 p |
The total number of mangosteens and apples is repeated. Make the total number of mangosteens and apples the same. LCM of 5 and 2 is 10.
|
Tomatoes |
Mangosteens |
Apples |
Number |
1 u |
4 u |
1 u |
Value |
$1.70 |
$1.90 |
$1.50 |
Total value |
1.7 u |
7.6 u |
1.5 u |
Total amount that Roshel earned
= 1.7 u + 7.6 u + 1.5 u
= 10.8 u
10.8 u = 151.20
1 u = 151.20 ÷ 10.8 = 14
Total number of fruits sold
= 1 u + 4 u + 1 u
= 6 u
= 6 x 14
= 84
Total number of fruits at first
= 84 ÷
14= 84 x 4
= 336
Total number of fruits at first
= 6 p + 5 p + 5 p
= 16 p
16 p = 336
1 p = 336 ÷ 16 = 21
Number of apples that Roshel had at first
= 5 p
= 5 x 21
= 105
Answer(s): 105