Hilda had some fruits at her stall.
13 of them were pomegranates,
15 of the remainder were kiwis and the rest were tomatoes. The amounts earned for each pomegranate, each kiwi and each tomato sold are $1.40, $1.70 and $1.30 respectively. The number of pomegranates sold to the number of kiwis sold to the number of tomatoes sold was 1 : 3 : 1. In total, she sold
15 of the fruits and earned $140.40. How many pomegranates did she have at first?
Pomegranates |
Kiwis |
Tomatoes |
Total |
1x5 |
2x5 |
3x5 |
|
1x2 |
4x2 |
|
5 p |
2 p |
8 p |
15 p |
The total number of kiwis and tomatoes is repeated. Make the total number of kiwis and tomatoes the same. LCM of 2 and 5 is 10.
|
Pomegranates |
Kiwis |
Tomatoes |
Number |
1 u |
3 u |
1 u |
Value |
$1.40 |
$1.70 |
$1.30 |
Total value |
1.4 u |
5.1 u |
1.3 u |
Total amount that Hilda earned
= 1.4 u + 5.1 u + 1.3 u
= 7.8 u
7.8 u = 140.40
1 u = 140.40 ÷ 7.8 = 18
Total number of fruits sold
= 1 u + 3 u + 1 u
= 5 u
= 5 x 18
= 90
Total number of fruits at first
= 90 ÷
15= 90 x 5
= 450
Total number of fruits at first
= 5 p + 2 p + 8 p
= 15 p
15 p = 450
1 p = 450 ÷ 15 = 30
Number of pomegranates that Hilda had at first
= 5 p
= 5 x 30
= 150
Answer(s): 150