Lucy had some fruits at her stall.
38 of them were limes,
14 of the remainder were apples and the rest were mandarin oranges. The amounts earned for each lime, each apple and each mandarin orange sold are $1.80, $1.60 and $1.70 respectively. The number of limes sold to the number of apples sold to the number of mandarin oranges sold was 2 : 3 : 1. In total, she sold
18 of the fruits and earned $181.80. How many mandarin oranges did she have at first?
Limes |
Apples |
Mandarin Oranges |
Total |
3x4 |
5x4 |
8x4 |
|
1x5 |
3x5 |
|
12 p |
5 p |
15 p |
32 p |
The total number of apples and mandarin oranges is repeated. Make the total number of apples and mandarin oranges the same. LCM of 5 and 4 is 20.
|
Limes |
Apples |
Mandarin Oranges |
Number |
2 u |
3 u |
1 u |
Value |
$1.80 |
$1.60 |
$1.70 |
Total value |
3.6 u |
4.8 u |
1.7 u |
Total amount that Lucy earned
= 3.6 u + 4.8 u + 1.7 u
= 10.1 u
10.1 u = 181.80
1 u = 181.80 ÷ 10.1 = 18
Total number of fruits sold
= 2 u + 3 u + 1 u
= 6 u
= 6 x 18
= 108
Total number of fruits at first
= 108 ÷
18= 108 x 8
= 864
Total number of fruits at first
= 12 p + 5 p + 15 p
= 32 p
32 p = 864
1 p = 864 ÷ 32 = 27
Number of mandarin oranges that Lucy had at first
= 15 p
= 15 x 27
= 405
Answer(s): 405