Sabrina had some fruits at her stall.
38 of them were limes,
14 of the remainder were dates and the rest were pears. The amounts earned for each lime, each date and each pear sold are $1.20, $1.70 and $1.40 respectively. The number of limes sold to the number of dates sold to the number of pears sold was 3 : 1 : 4. In total, she sold
18 of the fruits and earned $152.60. How many limes did she have at first?
Limes |
Dates |
Pears |
Total |
3x4 |
5x4 |
8x4 |
|
1x5 |
3x5 |
|
12 p |
5 p |
15 p |
32 p |
The total number of dates and pears is repeated. Make the total number of dates and pears the same. LCM of 5 and 4 is 20.
|
Limes |
Dates |
Pears |
Number |
3 u |
1 u |
4 u |
Value |
$1.20 |
$1.70 |
$1.40 |
Total value |
3.6 u |
1.7 u |
5.6 u |
Total amount that Sabrina earned
= 3.6 u + 1.7 u + 5.6 u
= 10.9 u
10.9 u = 152.60
1 u = 152.60 ÷ 10.9 = 14
Total number of fruits sold
= 3 u + 1 u + 4 u
= 8 u
= 8 x 14
= 112
Total number of fruits at first
= 112 ÷
18= 112 x 8
= 896
Total number of fruits at first
= 12 p + 5 p + 15 p
= 32 p
32 p = 896
1 p = 896 ÷ 32 = 28
Number of limes that Sabrina had at first
= 12 p
= 12 x 28
= 336
Answer(s): 336