Roshel had some fruits at her stall.
38 of them were peaches,
13 of the remainder were dragon fruits and the rest were papayas. The amounts earned for each peach, each dragon fruit and each papaya sold are $1.40, $1.70 and $1.20 respectively. The number of peaches sold to the number of dragon fruits sold to the number of papayas sold was 3 : 1 : 2. In total, she sold
14 of the fruits and earned $16.60. How many peaches did she have at first?
Peaches |
Dragon Fruits |
Papayas |
Total |
3x3 |
5x3 |
8x3 |
|
1x5 |
2x5 |
|
9 p |
5 p |
10 p |
24 p |
The total number of dragon fruits and papayas is repeated. Make the total number of dragon fruits and papayas the same. LCM of 5 and 3 is 15.
|
Peaches |
Dragon Fruits |
Papayas |
Number |
3 u |
1 u |
2 u |
Value |
$1.40 |
$1.70 |
$1.20 |
Total value |
4.2 u |
1.7 u |
2.4 u |
Total amount that Roshel earned
= 4.2 u + 1.7 u + 2.4 u
= 8.3 u
8.3 u = 16.60
1 u = 16.60 ÷ 8.3 = 2
Total number of fruits sold
= 3 u + 1 u + 2 u
= 6 u
= 6 x 2
= 12
Total number of fruits at first
= 12 ÷
14= 12 x 4
= 48
Total number of fruits at first
= 9 p + 5 p + 10 p
= 24 p
24 p = 48
1 p = 48 ÷ 24 = 2
Number of peaches that Roshel had at first
= 9 p
= 9 x 2
= 18
Answer(s): 18