Cindy had some fruits at her stall.
38 of them were pears,
14 of the remainder were oranges and the rest were mandarin oranges. The amounts earned for each pear, each orange and each mandarin orange sold are $1.30, $1.10 and $1.20 respectively. The number of pears sold to the number of oranges sold to the number of mandarin oranges sold was 5 : 2 : 3. In total, she sold
116 of the fruits and earned $110.70. How many pears did she have at first?
Pears |
Oranges |
Mandarin Oranges |
Total |
3x4 |
5x4 |
8x4 |
|
1x5 |
3x5 |
|
12 p |
5 p |
15 p |
32 p |
The total number of oranges and mandarin oranges is repeated. Make the total number of oranges and mandarin oranges the same. LCM of 5 and 4 is 20.
|
Pears |
Oranges |
Mandarin Oranges |
Number |
5 u |
2 u |
3 u |
Value |
$1.30 |
$1.10 |
$1.20 |
Total value |
6.5 u |
2.2 u |
3.6 u |
Total amount that Cindy earned
= 6.5 u + 2.2 u + 3.6 u
= 12.3 u
12.3 u = 110.70
1 u = 110.70 ÷ 12.3 = 9
Total number of fruits sold
= 5 u + 2 u + 3 u
= 10 u
= 10 x 9
= 90
Total number of fruits at first
= 90 ÷
116= 90 x 16
= 1440
Total number of fruits at first
= 12 p + 5 p + 15 p
= 32 p
32 p = 1440
1 p = 1440 ÷ 32 = 45
Number of pears that Cindy had at first
= 12 p
= 12 x 45
= 540
Answer(s): 540